QUBEE ACADEMY

Capitalization 😘👇👇👇
https://youtu.be/R-3RarHgp_Y
https://youtu.be/R-3RarHgp_Y

Next topic Grammar

Mee 'react' godha
❤️🙏👍🥰💯💪👏
Chemistry Grade 1* Unit 2
Coming soon....
👇👇👇👇👇👇👇👇
https://youtube.com/channel/UCLPTQfMXS6we7aTT4g9MwCw

✅ Atomic and Molecular Masses

✅ Mole Concept:

✅ Molarity:
Molarity is a measure of the concentration of a solution, defined as the number of moles of solute per liter of solution. It is represented by the symbol M and is calculated using the formula:

Molarity (M) = moles of solute / liters of solution

For example, if you have a solution containing 1 mole of sugar (C12H22O11) dissolved in enough water to make a total volume of 1 liter, the molarity of the solution would be:

Molarity (M) = 1 mole C12H22O11 / 1 liter solution = 1 M

✅ Molality:
Molality is another measure of concentration, defined as the number of moles of solute per kilogram of solvent. It is represented by the symbol m and is calculated using the formula:

Molality (m) = moles of solute / kilograms of solvent

For example, if you have a solution containing 1 mole of NaCl dissolved in 1 kilogram of water, the molality of the solution would be:

Molality (m) = 1 mole NaCl / 1 kilogram H2O = 1 m

✅ Percentage Composition:
Percentage composition is a measure of the percentage by mass of each element in a compound. To calculate the percentage composition, you need to know the molar mass of the compound and the molar mass of each element within the compound. The formula for percentage composition is:

Percentage composition (% by mass) = (molar mass of element / molar mass of compound) x 100%

For example, to calculate the percentage composition of carbon in glucose (C6H12O6), you would use the following values:

Molar mass of C6H12O6 = 180.156 g/mol
Molar mass of C = 12.011 g/mol
Molar mass of H = 1.008 g/mol
Molar mass of O = 16.00 g/mol

Percentage composition of carbon (% by mass) = (12.011 g/mol / 180.156 g/mol) x 100% ≈ 6.67%
Percentage composition of hydrogen (% by mass) = (12.011 g/mol / 180.156 g/mol) x 100% ≈ 6.67%
Percentage composition of oxygen (% by mass) = (16.00 g/mol / 180.156 g/mol) x 100% ≈ 33.33%
Join us👇👇👇👇
https://t.me/BililleAcadamy
https://t.me/BililleAcadamy
And 👇👇👇👇
https://t.me/qubeeacademy
https://t.me/qubeeacademy

https://t.me/qubeeacademy
https://t.me/qubeeacademy

Vidiyoo barnootaaf👇👇👇👇👇👇👇👇👇
https://youtube.com/channel/UCLPTQfMXS6we7aTT4g9MwCw

Mee 'react' godha
❤️🙏👍🥰💯💪
Chemistry Grade 1* Unit 2
Coming soon....
👇👇👇👇👇👇👇👇
https://youtube.com/channel/UCLPTQfMXS6we7aTT4g9MwCw